Chemistry

Chemistry

Problem

2.8 g of N2N_2 gas at 300 K and 20 atm was allowed to expand isothermally against a constant external pressure of 1 atm. Calculate ΔU\Delta U , qq and WW for the gas.
Intuitive explanation

This problem tests your understanding of isothermal expansion and the first law of thermodynamics. The key insight is that for an ideal gas, internal energy ΔU\Delta U depends only on temperature—since temperature is constant here, ΔU=0\Delta U = 0 immediately. From there, the first law (ΔU=q+W\Delta U = q + W) tells you that qq and WW must be equal and opposite. Calculate work using W=−PextΔVW = -P_{\text{ext}} \Delta V (where ΔV\Delta V comes from the ideal gas law), then use energy conservation to find heat.

Intuitive explanation

This problem tests your understanding of isothermal expansion and the first law of thermodynamics. The key insight is that for an ideal gas, internal energy ΔU\Delta U depends only on temperature—since temperature is constant here, ΔU=0\Delta U = 0 immediately. From there, the first law (ΔU=q+W\Delta U = q + W) tells you that qq and WW must be equal and opposite. Calculate work using W=−PextΔVW = -P_{\text{ext}} \Delta V (where ΔV\Delta V comes from the ideal gas law), then use energy conservation to find heat.

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