Chemistry
Chemistry
Problem
50 mL of 0.3 M acetic acid is shaken with 5 g activated charcoal. The concentration of acetic acid is reduced to 1/3 of original molarity. The mass of acetic acid adsorbed per g of charcoal is:Intuitive explanation
Adsorption is about molecules sticking to a solid surface—here, acetic acid molecules clinging to charcoal. The key is tracking how much acid disappears from solution: the difference between what you started with and what remains is exactly what the charcoal grabbed. Calculate moles lost, convert to mass, then divide by the grams of charcoal to get the adsorption capacity per gram.
Intuitive explanation
Adsorption is about molecules sticking to a solid surface—here, acetic acid molecules clinging to charcoal. The key is tracking how much acid disappears from solution: the difference between what you started with and what remains is exactly what the charcoal grabbed. Calculate moles lost, convert to mass, then divide by the grams of charcoal to get the adsorption capacity per gram.