Problem

Problem

A convergent lens with a focal length of f=10 cmf = 10 \text{ cm} is cut into two halves that are then moved apart to a distance of d=0.5 mmd = 0.5 \text{ mm} (a double lens). Find the fringe width on screen at a distance of 60 cm60 \text{ cm} behind the lens if a point source of monochromatic light ( λ=5000 A˚\lambda = 5000 \text{ \AA} ) is placed in front of the lens at a distance of a=15 cma = 15 \text{ cm} from it.
Intuitive explanation

When you cut a lens in half and separate the pieces, you create two coherent light sources—each half acts like a separate lens forming its own image of the point source. These two images become coherent secondary sources that interfere on the screen, much like a double-slit setup. The key is finding where each half-lens focuses the light (using the lens equation), then treating the separation between those image points as your effective "slit separation" in the interference formula β=λDd\beta = \frac{\lambda D}{d}, where DD is the distance from the images to the screen.

Intuitive explanation

When you cut a lens in half and separate the pieces, you create two coherent light sources—each half acts like a separate lens forming its own image of the point source. These two images become coherent secondary sources that interfere on the screen, much like a double-slit setup. The key is finding where each half-lens focuses the light (using the lens equation), then treating the separation between those image points as your effective "slit separation" in the interference formula β=λDd\beta = \frac{\lambda D}{d}, where DD is the distance from the images to the screen.

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