Physics

Physics

Problem

A series RLC circuit resonates at 2.0 kHz when its capacitor has capacitance C. If the capacitance is increased to 5C, what will be the new resonant frequency? a) 4.5 kHz4.5\text{ kHz} b) 0.9 kHz0.9\text{ kHz} c) 10 kHz10\text{ kHz} d) 0.4 kHz0.4\text{ kHz}
Intuitive explanation

Resonant frequency in an RLC circuit depends on the relationship between inductance and capacitance through f0=12πLCf_0 = \frac{1}{2\pi\sqrt{LC}}. The key insight is recognizing how frequency scales when you change capacitance: since ff is inversely proportional to C\sqrt{C}, increasing capacitance by a factor of 5 means the frequency decreases by a factor of 5\sqrt{5}. You don't need to know LL or the actual resistance—just use the ratio of the two frequencies.

Intuitive explanation

Resonant frequency in an RLC circuit depends on the relationship between inductance and capacitance through f0=12πLCf_0 = \frac{1}{2\pi\sqrt{LC}}. The key insight is recognizing how frequency scales when you change capacitance: since ff is inversely proportional to C\sqrt{C}, increasing capacitance by a factor of 5 means the frequency decreases by a factor of 5\sqrt{5}. You don't need to know LL or the actual resistance—just use the ratio of the two frequencies.

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