Mathematics

Mathematics

Problem

9. A point on the hypotenuse of a triangle is at distance aa and bb from the sides of the triangle. Show that the minimum length of the hypotenuse is (a23+b23)32\left(a^{\frac{2}{3}}+b^{\frac{2}{3}}\right)^{\frac{3}{2}}.
Intuitive explanation

The key is to set up a coordinate system with the right angle at the origin and legs along the axes, then use the constraint that a point on the hypotenuse maintains fixed perpendicular distances aa and bb to those legs. This transforms the problem into minimizing the hypotenuse length c=x+yc = x + y subject to the geometric constraint that the point's distances to the legs equal aa and bb—which forces a relationship between the leg lengths. Calculus or the AM-GM inequality applied to the reciprocals of the legs will reveal that the minimum occurs at a specific ratio, leading to the elegant fractional-power form.

Intuitive explanation

The key is to set up a coordinate system with the right angle at the origin and legs along the axes, then use the constraint that a point on the hypotenuse maintains fixed perpendicular distances aa and bb to those legs. This transforms the problem into minimizing the hypotenuse length c=x+yc = x + y subject to the geometric constraint that the point's distances to the legs equal aa and bb—which forces a relationship between the leg lengths. Calculus or the AM-GM inequality applied to the reciprocals of the legs will reveal that the minimum occurs at a specific ratio, leading to the elegant fractional-power form.

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