Physics

Physics

Problem

Which one of the following equations represents a wave of amplitude 0.03 m0.03\,\text{m} travelling in the negative xx–direction with angular frequency 40π rad s−140\pi\,\text{rad\,s}^{-1}? a) y=0.03sin⁡(5πx−40πt)y=0.03\sin(5\pi x-40\pi t) b) y=0.03sin⁡(5πx+40πt)y=0.03\sin(5\pi x+40\pi t) c) y=0.03sin⁡(5πx+20πt)y=0.03\sin(5\pi x+20\pi t) d) y=0.03sin⁡(40πx+5πt)y=0.03\sin(40\pi x+5\pi t)
Intuitive explanation

A traveling wave's equation reveals its direction through the sign of the xx term: positive xx means the wave moves left (negative direction), while negative xx means it moves right. You need to match three parameters—amplitude A=0.03 mA = 0.03\,\text{m}, angular frequency ω=40π rad s−1\omega = 40\pi\,\text{rad\,s}^{-1}, and the correct sign pattern—to the standard form y=Asin⁡(ωt+kx+ϕ)y = A\sin(\omega t + kx + \phi) or y=Acos⁡(ωt+kx+ϕ)y = A\cos(\omega t + kx + \phi).

Intuitive explanation

A traveling wave's equation reveals its direction through the sign of the xx term: positive xx means the wave moves left (negative direction), while negative xx means it moves right. You need to match three parameters—amplitude A=0.03 mA = 0.03\,\text{m}, angular frequency ω=40π rad s−1\omega = 40\pi\,\text{rad\,s}^{-1}, and the correct sign pattern—to the standard form y=Asin⁡(ωt+kx+ϕ)y = A\sin(\omega t + kx + \phi) or y=Acos⁡(ωt+kx+ϕ)y = A\cos(\omega t + kx + \phi).

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