Physics

Physics

Problem

A tuning fork produces sound of frequency 512 Hz512\,\text{Hz}. Calculate its time period. a) 1.23×10−2 s1.23\times10^{-2}\,\text{s} b) 1.00×10−3 s1.00\times10^{-3}\,\text{s} c) 1.95×10−3 s1.95\times10^{-3}\,\text{s} d) 1.95×10−2 s1.95\times10^{-2}\,\text{s}
Intuitive explanation

The time period and frequency are reciprocals—they measure the same oscillation from opposite angles. Frequency tells you how many complete vibrations happen per second, while time period tells you how long one single vibration takes. To find the period, just flip the frequency upside down using T=1fT = \frac{1}{f}.

Intuitive explanation

The time period and frequency are reciprocals—they measure the same oscillation from opposite angles. Frequency tells you how many complete vibrations happen per second, while time period tells you how long one single vibration takes. To find the period, just flip the frequency upside down using T=1fT = \frac{1}{f}.

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