Abstract Algebra: Theory and Applications · Problem 22.4.17
Galois Theory — Thomas Judson
Mathematics — Abstract Algebra · finite-fields-separable-extensions
Problem
Let be fields. If is a separable extension of , show that is also separable extension of . Hint. If , then .Intuitive explanation
The key insight is that separability is about minimal polynomials having no repeated roots, and this property is inherited by larger fields. When is separable over , every element of has a minimal polynomial over with distinct roots. Since any element of also lies in , its minimal polynomial over must divide its minimal polynomial over —and a polynomial with distinct roots can only have divisors with distinct roots. The hint reminds you that coefficients in are automatically in , so you're not losing information about the original minimal polynomial.
Intuitive explanation
The key insight is that separability is about minimal polynomials having no repeated roots, and this property is inherited by larger fields. When is separable over , every element of has a minimal polynomial over with distinct roots. Since any element of also lies in , its minimal polynomial over must divide its minimal polynomial over —and a polynomial with distinct roots can only have divisors with distinct roots. The hint reminds you that coefficients in are automatically in , so you're not losing information about the original minimal polynomial.