Problem

Problem

In Young's double-slit interference experiment, if the slit separation is made threefold, the fringe width becomes (1) sixfold (2) threefold (3) 3/63/6 -fold (4) 1/31/3 -fold
Intuitive explanation

The key insight is that fringe width depends inversely on slit separation—when slits are farther apart, the light waves from each slit diverge less before meeting, so the interference pattern compresses. Specifically, fringe width β=λDd\beta = \frac{\lambda D}{d}, where dd is slit separation. If you triple dd, you're dividing the denominator by 3, so the fringe width becomes one-third its original value.

Intuitive explanation

The key insight is that fringe width depends inversely on slit separation—when slits are farther apart, the light waves from each slit diverge less before meeting, so the interference pattern compresses. Specifically, fringe width β=λDd\beta = \frac{\lambda D}{d}, where dd is slit separation. If you triple dd, you're dividing the denominator by 3, so the fringe width becomes one-third its original value.

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