Mathematics

Mathematics

Problem

Let f(1)=−2f(1) = -2 and f′(x)≥4.2f'(x) \geq 4.2 for 1≤x≤61 \leq x \leq 6. The smallest possible value of f(6)f(6) is (a) 9 (b) 12 (c) 15 (d) 19 (a) 9 (b) 12 (c) 15 (d) 19
Intuitive explanation

This problem connects the derivative (rate of change) to the total change in a function using the Mean Value Theorem. Since f′(x)f'(x) has a lower bound, the function must increase by at least some minimum amount over the interval—and you want the smallest possible value of f(6)f(6), so you should use the minimum allowed rate of change throughout. The key is linking the derivative constraint to the distance traveled: total change equals (minimum slope) × (interval width).

Intuitive explanation

This problem connects the derivative (rate of change) to the total change in a function using the Mean Value Theorem. Since f′(x)f'(x) has a lower bound, the function must increase by at least some minimum amount over the interval—and you want the smallest possible value of f(6)f(6), so you should use the minimum allowed rate of change throughout. The key is linking the derivative constraint to the distance traveled: total change equals (minimum slope) × (interval width).

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