Mathematics
Mathematics
Problem
Let and for . The smallest possible value of is (a) 9 (b) 12 (c) 15 (d) 19 (a) 9 (b) 12 (c) 15 (d) 19Intuitive explanation
This problem connects the derivative (rate of change) to the total change in a function using the Mean Value Theorem. Since has a lower bound, the function must increase by at least some minimum amount over the interval—and you want the smallest possible value of , so you should use the minimum allowed rate of change throughout. The key is linking the derivative constraint to the distance traveled: total change equals (minimum slope) × (interval width).
Intuitive explanation
This problem connects the derivative (rate of change) to the total change in a function using the Mean Value Theorem. Since has a lower bound, the function must increase by at least some minimum amount over the interval—and you want the smallest possible value of , so you should use the minimum allowed rate of change throughout. The key is linking the derivative constraint to the distance traveled: total change equals (minimum slope) × (interval width).