Mathematics

Mathematics

Problem

Determine the value of ddx[e2x−1]\dfrac{d}{dx}\bigl[e^{2x-1}\bigr] at x=1x=1. a) ee b) 2e2e c) 4e4e d) e2e^{2}
Intuitive explanation

The key here is the chain rule for exponential functions. When you differentiate eu(x)e^{u(x)}, you get eu(x)⋅u′(x)e^{u(x)} \cdot u'(x)—the exponential stays, but you multiply by the derivative of the exponent. Once you have the derivative formula, evaluating at x=1x=1 is just substitution.

Intuitive explanation

The key here is the chain rule for exponential functions. When you differentiate eu(x)e^{u(x)}, you get eu(x)⋅u′(x)e^{u(x)} \cdot u'(x)—the exponential stays, but you multiply by the derivative of the exponent. Once you have the derivative formula, evaluating at x=1x=1 is just substitution.

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