Mathematics

Mathematics

Problem

(a) Define the term “principal value” of an inverse trigonometric function. (b) State the principal value ranges of arcsin⁡x\arcsin x, arccos⁡x\arccos x and arctan⁡x\arctan x. (c) For each of the following expressions, decide whether the angle shown is the principal value of the inverse trigonometric expression indicated. Give a brief reason for every answer. (i) arcsin⁡(12)=5π6\arcsin\left(\dfrac12\right)=\dfrac{5\pi}{6} (ii) arccos⁡(−34)=2π3\arccos\left(-\dfrac34\right)=\dfrac{2\pi}{3} (iii) arctan⁡(2)=5π6\arctan(2)=\dfrac{5\pi}{6} (d) Rewrite every incorrect equality in part (c) with the correct principal value.
Intuitive explanation

Inverse trigonometric functions are multi-valued because many angles produce the same sine, cosine, or tangent—so we restrict them to a single, agreed-upon range called the principal value range. This restriction ensures each input has exactly one output, making arcsin⁡\arcsin, arccos⁡\arccos, and arctan⁡\arctan true functions. To check whether a given angle is the principal value, you verify both that the trigonometric equation is true and that the angle lies within the designated range for that function.

Intuitive explanation

Inverse trigonometric functions are multi-valued because many angles produce the same sine, cosine, or tangent—so we restrict them to a single, agreed-upon range called the principal value range. This restriction ensures each input has exactly one output, making arcsin⁡\arcsin, arccos⁡\arccos, and arctan⁡\arctan true functions. To check whether a given angle is the principal value, you verify both that the trigonometric equation is true and that the angle lies within the designated range for that function.

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