Physics

This is a kinematics problem where you have distance, initial velocity, and acceleration, but need to find time—a classic setup for the kinematic equation that doesn't require final velocity. The key insight is recognizing that $s = v_0 t + \frac{1}{2}at^2$ gives you a quadratic equation in $t$, which you can solve directly by rearranging and using the quadratic formula. Once you substitute the known values, you'll get two mathematical solutions, but only one makes physical sense for this scenario.

This is a kinematics problem where you have distance, initial velocity, and acceleration, but need to find time—a classic setup for the kinematic equation that doesn't require final velocity. The key insight is recognizing that $s = v_0 t + \frac{1}{2}at^2$ gives you a quadratic equation in $t$, which you can solve directly by rearranging and using the quadratic formula. Once you substitute the known values, you'll get two mathematical solutions, but only one makes physical sense for this scenario.