Classical Mechanics (Kibble & Berkshire) · Problem 13.11
Hamilton's equations and phase space — T.W.B. Kibble, F.H. Berkshire
Physics — Mechanics · hamiltons-principle
Problem
A certain oscillator with generalised coordinate has Lagrangian Verify that is a motion of the oscillator, and show directly that it makes the action functional stationary in any time interval . For the time interval , find the variation in the action functional corresponding to the variations (i) , (ii) , where is a small parameter. Deduce that the motion does not make a minimum or a maximum.Intuitive explanation
The action functional is stationary when the Euler-Lagrange equation is satisfied—this is the principle of least action. To verify is a true motion, substitute it into the equation of motion and check it works. Then, to show stationarity directly, compute the first variation by perturbing slightly and confirming the linear term in vanishes. Finally, test two different perturbations: if one increases the action and another decreases it, the stationary point is a saddle, not an extremum—revealing the deep difference between "stationary" (zero first variation) and "extremum" (definite sign of second variation).
Intuitive explanation
The action functional is stationary when the Euler-Lagrange equation is satisfied—this is the principle of least action. To verify is a true motion, substitute it into the equation of motion and check it works. Then, to show stationarity directly, compute the first variation by perturbing slightly and confirming the linear term in vanishes. Finally, test two different perturbations: if one increases the action and another decreases it, the stationary point is a saddle, not an extremum—revealing the deep difference between "stationary" (zero first variation) and "extremum" (definite sign of second variation).