Physics

Physics

Problem

A student is investigating how the nature of the image produced by a thin convex lens changes as the object is moved to different positions along the principal axis. a. (i) Explain qualitatively how the position, size and nature of the image vary when the object is placed (a) beyond 2F2F, (b) at 2F2F, (c) between FF and 2F2F, and (d) between the optical centre and FF of the lens. b. (ii) Draw a neat and properly labelled ray diagram for case (c) only. c. (iii) Give a reason why a real image formed by the convex lens can be obtained on a screen whereas a concave lens cannot project a sharp image on a screen for any position of the object.
Intuitive explanation

The key insight is that a convex lens acts like a "position detector"—where you place the object determines everything about the image (size, orientation, and whether it's real or virtual). The critical distances are the focal length ff and the center of curvature 2f2f: beyond 2f2f gives a small real image, between ff and 2f2f gives a large real image, and inside ff gives a virtual magnified image. By systematically moving the object and observing how the image changes, you'll see the lens equation 1f=1do+1di\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} play out in real space.

Intuitive explanation

The key insight is that a convex lens acts like a "position detector"—where you place the object determines everything about the image (size, orientation, and whether it's real or virtual). The critical distances are the focal length ff and the center of curvature 2f2f: beyond 2f2f gives a small real image, between ff and 2f2f gives a large real image, and inside ff gives a virtual magnified image. By systematically moving the object and observing how the image changes, you'll see the lens equation 1f=1do+1di\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} play out in real space.

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