Physics

Physics

Problem

Assertion : Ratio of maximum intensity and minimum intensity in interference is 25 : 1. The amplitude ratio of two waves should be 3 : 2. Reason : Imax⁡Imin⁡=(A1+A2A1−A2)2\frac{I_{\max}}{I_{\min}} = \left( \frac{A_1 + A_2}{A_1 - A_2} \right)^2
Intuitive explanation

Interference intensity depends on how two waves combine—constructively at maxima and destructively at minima. The key insight is that intensity scales with the square of amplitude, so the ratio of max to min intensities is determined by the ratio of the sum and difference of the individual amplitudes. You're working backwards from a known intensity ratio to find what amplitude ratio must produce it.

Intuitive explanation

Interference intensity depends on how two waves combine—constructively at maxima and destructively at minima. The key insight is that intensity scales with the square of amplitude, so the ratio of max to min intensities is determined by the ratio of the sum and difference of the individual amplitudes. You're working backwards from a known intensity ratio to find what amplitude ratio must produce it.

Browse the problem library