If ∫cos⁡6x+cos⁡9x1−2cos⁡5xdx=−sin⁡4xk−sin⁡x+C\int \frac{\cos 6x + \cos 9x}{1 - 2 \cos 5x} dx = -\frac{\sin 4x}{k} - \sin x + C , t…

Mathematics

Problem

If ∫cos⁡6x+cos⁡9x1−2cos⁡5xdx=−sin⁡4xk−sin⁡x+C\int \frac{\cos 6x + \cos 9x}{1 - 2 \cos 5x} dx = -\frac{\sin 4x}{k} - \sin x + C , then the value of kk is .....
Intuitive explanation

The key is to recognize that the numerator can be factored using sum-to-product formulas, and that this factorization will share a common factor with the denominator. Once you simplify by canceling, you'll get a much simpler integrand—likely a sum of basic trig functions. Match your result to the given answer form to find kk.

Intuitive explanation

The key is to recognize that the numerator can be factored using sum-to-product formulas, and that this factorization will share a common factor with the denominator. Once you simplify by canceling, you'll get a much simpler integrand—likely a sum of basic trig functions. Match your result to the given answer form to find kk.

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