Introduction to Classical Mechanics · Problem 11.19

Relativity (Kinematics) — Morin

Physics — Mechanics · modified-twin-paradox

Problem

Consider the following variation of the twin paradox. AA, BB, and CC each have a clock. In AA's reference frame, BB flies past AA with speed vv to the right. When BB passes AA, they both set their clocks to zero. Also, in AA's reference frame, CC starts far to the right and moves to the left with speed vv. When BB and CC pass each other, CC sets his clock to read the same as BB's. Finally, when CC passes AA, they compare the readings on their clocks. At this moment, let AA's clock read TAT_A, and let CC's clock read TCT_C. (a) Working in AA's frame, show that TC=TA/γT_C = T_A/\gamma, where γ=1/1−v2/c2\gamma = 1/\sqrt{1 - v^2/c^2}. (b) Working in BB's frame, show again that TC=TA/γT_C = T_A/\gamma. (c) Working in CC's frame, show again that TC=TA/γT_C = T_A/\gamma.
Intuitive explanation

The key to this problem is understanding that proper time (time measured by a clock moving with an observer) is invariant across reference frames, even though simultaneity is relative. Each observer ages according to their own proper time, which depends on their motion through spacetime. By carefully tracking which events are simultaneous in each frame and how moving clocks run slow, you'll see that all three frames agree on the final clock readings—even though they disagree on when certain events happened. The factor γ\gamma appears because BB and CC are moving relative to AA, so their clocks tick slower in AA's frame, and this effect persists when you transform to their frames using relativity of simultaneity.

Intuitive explanation

The key to this problem is understanding that proper time (time measured by a clock moving with an observer) is invariant across reference frames, even though simultaneity is relative. Each observer ages according to their own proper time, which depends on their motion through spacetime. By carefully tracking which events are simultaneous in each frame and how moving clocks run slow, you'll see that all three frames agree on the final clock readings—even though they disagree on when certain events happened. The factor γ\gamma appears because BB and CC are moving relative to AA, so their clocks tick slower in AA's frame, and this effect persists when you transform to their frames using relativity of simultaneity.

Related theory

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