Physics

Physics

Problem

a. Show that the apparent weight W′W' of a body of mass mm placed on a weighing machine inside a lift descending with uniform acceleration a (a<g)a\,(a<g) is W′=m(g−a)W' = m(g - a). b. What will be the reading of the weighing machine when the lift cable snaps and the lift falls freely? Express your answer in terms of mm.
Intuitive explanation

The key to apparent weight is recognizing that a scale reads the normal force pushing up on you, not your true weight. When the lift accelerates downward, the net force on your body must point downward (toward the center of acceleration), so the upward normal force becomes smaller than mgmg—you feel lighter. In free fall, there's no normal force at all because gravity alone provides all the acceleration needed, so the scale reads zero.

Intuitive explanation

The key to apparent weight is recognizing that a scale reads the normal force pushing up on you, not your true weight. When the lift accelerates downward, the net force on your body must point downward (toward the center of acceleration), so the upward normal force becomes smaller than mgmg—you feel lighter. In free fall, there's no normal force at all because gravity alone provides all the acceleration needed, so the scale reads zero.

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