Problem

Problem

Calcium sulphate is found in nature in two forms, anhydrous calcium sulphate and hydrated calcium sulphate. When anhydrous calcium sulphate is heated with coke, sulphur dioxide gas is obtained. When hydrated calcium sulphate is heated to 200∘C200^\circ\text{C}, it forms anhydrous salt. What is the product formed when hydrated CaSO4\text{CaSO}_4 is heated to 125∘C125^\circ\text{C} instead of 200∘C200^\circ\text{C} ? a. (CaSO4)2⋅2H2O(\text{CaSO}_4)_2 \cdot 2\text{H}_2\text{O} b. CaSO4⋅34H2O\text{CaSO}_4 \cdot \frac{3}{4}\text{H}_2\text{O} c. CaSO4\text{CaSO}_4 d. CaO+SO3\text{CaO} + \text{SO}_3
Intuitive explanation

When you heat a hydrated salt, water doesn't all leave at once—different amounts of water escape at different temperatures, creating intermediate hydration states. Calcium sulphate hydrate is special: it has a "partial dehydration" point where only some water molecules are removed, leaving a specific lower-hydrate form stable at that intermediate temperature. At 125°C125°\text{C}, you're heating enough to lose water, but not enough to reach the fully anhydrous form, so you'll get a compound with fewer water molecules than the original but more than zero.

Intuitive explanation

When you heat a hydrated salt, water doesn't all leave at once—different amounts of water escape at different temperatures, creating intermediate hydration states. Calcium sulphate hydrate is special: it has a "partial dehydration" point where only some water molecules are removed, leaving a specific lower-hydrate form stable at that intermediate temperature. At 125°C125°\text{C}, you're heating enough to lose water, but not enough to reach the fully anhydrous form, so you'll get a compound with fewer water molecules than the original but more than zero.

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