Mathematics

Mathematics

Problem

If lim⁡x→0f(x)x2=a\lim_{x \rightarrow 0} \frac{f(x)}{x^2} = a , lim⁡x→0f(1−cos⁡x)g(x)⋅sin⁡2x=b\lim_{x \rightarrow 0} \frac{f(1-\cos x)}{g(x) \cdot \sin^2 x} = b ( b≠0b \neq 0 ), then lim⁡x→0g(1−cos⁡2x)x4\lim_{x \rightarrow 0} \frac{g(1-\cos 2x)}{x^4} is (a) 4a/b4a/b (b) a/4ba/4b (c) a/ba/b (d) None.
Intuitive explanation

The first condition tells you that f(x)f(x) behaves like ax2ax^2 near zero—this is your anchor for understanding ff's growth rate. The second condition involves f(1−cos⁡x)f(1-\cos x), which means you need to substitute the argument 1−cos⁡x1-\cos x into that same quadratic behavior, then use the fact that 1−cos⁡x≈x221-\cos x \approx \frac{x^2}{2} to extract information about g(x)g(x). Once you know how gg behaves, scale the final expression using 1−cos⁡2x≈2x21-\cos 2x \approx 2x^2 and simplify.

Intuitive explanation

The first condition tells you that f(x)f(x) behaves like ax2ax^2 near zero—this is your anchor for understanding ff's growth rate. The second condition involves f(1−cos⁡x)f(1-\cos x), which means you need to substitute the argument 1−cos⁡x1-\cos x into that same quadratic behavior, then use the fact that 1−cos⁡x≈x221-\cos x \approx \frac{x^2}{2} to extract information about g(x)g(x). Once you know how gg behaves, scale the final expression using 1−cos⁡2x≈2x21-\cos 2x \approx 2x^2 and simplify.

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