Mathematics

Mathematics

Problem

Suppose AA and BB are mutually exclusive, and that A′A' and B′B' are mutually exclusive. Find P(A∩B)P(A \cap B).
Intuitive explanation

The key insight is to translate "mutually exclusive" into equations and then use them together. If AA and BB can't both happen, then P(A∩B)=0P(A \cap B) = 0. But the second condition—that A′A' and B′B' are also mutually exclusive—tells you something about what must happen. Think about what it means for the complements to have no overlap, and how that constrains the original events.

Intuitive explanation

The key insight is to translate "mutually exclusive" into equations and then use them together. If AA and BB can't both happen, then P(A∩B)=0P(A \cap B) = 0. But the second condition—that A′A' and B′B' are also mutually exclusive—tells you something about what must happen. Think about what it means for the complements to have no overlap, and how that constrains the original events.

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