The Resonant Ice Cave · AI Generator #GEN-19508D8F

Physics

Problem

A spelunker discovers a narrow ice cave that produces a haunting musical tone when wind blows across its entrance. The cave can be modeled as a cylindrical tube of length L=12.0  mL = 12.0\;\text{m} that is closed at one end by solid ice and open at the other end where wind flows. The spelunker notices that the fundamental resonant frequency changes as the temperature drops. At temperature T1=273  KT_1 = 273\;\text{K} (melting point), the fundamental frequency is f1=14.3  Hzf_1 = 14.3\;\text{Hz}. When the temperature drops to T2=243  KT_2 = 243\;\text{K} (typical winter cave temperature), the frequency becomes f2f_2. However, there's a twist: as the temperature drops, a thin layer of ice forms on the inner walls of the cave, effectively reducing the cave's cross-sectional area and thus its length by ΔL=0.15  m\Delta L = 0.15\;\text{m}. The spelunker wants to determine whether the frequency change is dominated by the temperature effect on sound speed or by the geometric change. (a) Calculate the fundamental frequency f2f_2 at the lower temperature, accounting for both effects. (b) What would the frequency be if only the temperature effect occurred (no change in length)? (c) What would the frequency be if only the geometric effect occurred (no temperature change)? Assume air behaves as an ideal gas and use γ=1.4\gamma = 1.4 for air.
Intuitive explanation

This problem asks you to separate two competing effects on resonance: how sound speed changes with temperature, and how the physical dimensions shrink. For a tube closed at one end, the fundamental frequency depends on f=v/(4L)f = v/(4L), where vv is sound speed and LL is length—so both the numerator and denominator shift as conditions change. The key insight is to calculate vv at each temperature using the ideal gas relationship (v∝Tv \propto \sqrt{T}), then compare three scenarios: both effects together, temperature alone, and geometry alone. This reveals which effect dominates the frequency shift the spelunker hears.

Intuitive explanation

This problem asks you to separate two competing effects on resonance: how sound speed changes with temperature, and how the physical dimensions shrink. For a tube closed at one end, the fundamental frequency depends on f=v/(4L)f = v/(4L), where vv is sound speed and LL is length—so both the numerator and denominator shift as conditions change. The key insight is to calculate vv at each temperature using the ideal gas relationship (v∝Tv \propto \sqrt{T}), then compare three scenarios: both effects together, temperature alone, and geometry alone. This reveals which effect dominates the frequency shift the spelunker hears.

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