Principles of Quantum Mechanics · Problem 19.2

Scattering Theory — R. Shankar

Physics — Quantum Mechanics · optical-theorem

Problem

Verify the optical theorem for the case of scattering from a hard sphere (in the Born approximation). The optical theorem states: σtot=4πkIm f(θ=0)\sigma_{\text{tot}} = \frac{4\pi}{k} \text{Im}\, f(\theta = 0) Check that the total cross section computed from ∫∣f∣2dΩ\int |f|^2 d\Omega equals 4πk Im f(0)\frac{4\pi}{k}\,\text{Im}\,f(0).
Intuitive explanation

The optical theorem connects the imaginary part of the forward scattering amplitude to the total cross section—a deep result linking destructive interference (forward scattering) to overall absorption of the incident wave. For a hard sphere in the Born approximation, you'll compute the scattering amplitude f(θ)f(\theta) explicitly, extract its imaginary part at θ=0\theta=0, then verify it matches the integrated differential cross section ∫∣f(θ)∣2dΩ\int |f(\theta)|^2 d\Omega. This check reveals how quantum unitarity constrains scattering: the forward amplitude's phase shift accounts for all particles removed from the beam.

Intuitive explanation

The optical theorem connects the imaginary part of the forward scattering amplitude to the total cross section—a deep result linking destructive interference (forward scattering) to overall absorption of the incident wave. For a hard sphere in the Born approximation, you'll compute the scattering amplitude f(θ)f(\theta) explicitly, extract its imaginary part at θ=0\theta=0, then verify it matches the integrated differential cross section ∫∣f(θ)∣2dΩ\int |f(\theta)|^2 d\Omega. This check reveals how quantum unitarity constrains scattering: the forward amplitude's phase shift accounts for all particles removed from the beam.

Related theory

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