Mathematics

Mathematics

Problem

What is the derivative of cot⁡x\cot x with respect to xx? a) −csc⁡xcot⁡x-\csc x\cot x b) csc⁡2x\csc^{2} x c) −csc⁡2x-\csc^{2} x d) sec⁡2x\sec^{2} x
Intuitive explanation

The key is to remember that cot⁡x=cos⁡xsin⁡x\cot x = \frac{\cos x}{\sin x}, so you can use the quotient rule rather than memorizing a formula. When you apply quotient rule carefully—taking the derivative of the numerator and denominator, then combining—you'll notice the result simplifies nicely using the Pythagorean identity sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1. The final answer will be a clean, single trigonometric expression.

Intuitive explanation

The key is to remember that cot⁡x=cos⁡xsin⁡x\cot x = \frac{\cos x}{\sin x}, so you can use the quotient rule rather than memorizing a formula. When you apply quotient rule carefully—taking the derivative of the numerator and denominator, then combining—you'll notice the result simplifies nicely using the Pythagorean identity sin⁡2x+cos⁡2x=1\sin^2 x + \cos^2 x = 1. The final answer will be a clean, single trigonometric expression.

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