Problem

Problem

In a △ABC\triangle ABC , if Rr≤2\frac{R}{r} \le 2 , then show that the triangle is equilateral.
Intuitive explanation

The key insight is that the ratio Rr\frac{R}{r} (circumradius to inradius) is minimized when a triangle is equilateral, and this minimum value is exactly 2. You'll want to express both RR and rr in terms of the triangle's sides and angles, then use the constraint Rr≤2\frac{R}{r} \le 2 to show it forces equality—which only happens for an equilateral triangle. This is a beautiful example of how geometric inequalities can characterize special triangles.

Intuitive explanation

The key insight is that the ratio Rr\frac{R}{r} (circumradius to inradius) is minimized when a triangle is equilateral, and this minimum value is exactly 2. You'll want to express both RR and rr in terms of the triangle's sides and angles, then use the constraint Rr≤2\frac{R}{r} \le 2 to show it forces equality—which only happens for an equilateral triangle. This is a beautiful example of how geometric inequalities can characterize special triangles.

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