Mathematics

Mathematics

Problem

For θ=−19π6\theta = -\dfrac{19\pi}{6}, determine the ordered pair (sin⁡θ, cot⁡θ)(\sin\theta,\,\cot\theta). a) (−12, −3)\left(-\dfrac12,\,-\sqrt3\right) b) (12, 3)\left(\dfrac12,\,\sqrt3\right) c) (12, −3)\left(\dfrac12,\,-\sqrt3\right) d) (12, −13)\left(\dfrac12,\,-\dfrac1{\sqrt3}\right)
Intuitive explanation

The key is recognizing that sine and cotangent are periodic functions, so you can "unwrap" any angle by adding or subtracting full rotations (2π2\pi) until you land in a familiar range. Once you've reduced θ\theta to a coterminal angle between 00 and 2π2\pi, you'll recognize a standard position angle whose trig values you know. Then compute both sin⁡θ\sin\theta and cot⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{\cos\theta}{\sin\theta} from that reference angle.

Intuitive explanation

The key is recognizing that sine and cotangent are periodic functions, so you can "unwrap" any angle by adding or subtracting full rotations (2π2\pi) until you land in a familiar range. Once you've reduced θ\theta to a coterminal angle between 00 and 2π2\pi, you'll recognize a standard position angle whose trig values you know. Then compute both sin⁡θ\sin\theta and cot⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{\cos\theta}{\sin\theta} from that reference angle.

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