Physics

Physics

Problem

A plane electromagnetic wave travels through glass of refractive index n=1.5n = 1.5 with an electric field amplitude of 6 V m−16\,\text{V m}^{-1}. Take c=3.0×108 m s−1c = 3.0 \times 10^{8}\,\text{m s}^{-1}. Determine the magnetic field amplitude B0B_0 inside the glass. a) 2.0×10−8 T2.0 \times 10^{-8}\,\text{T} b) 4.5×10−8 T4.5 \times 10^{-8}\,\text{T} c) 3.0×10−8 T3.0 \times 10^{-8}\,\text{T} d) 1.3×10−8 T1.3 \times 10^{-8}\,\text{T}
Intuitive explanation

The key is recognizing that the relationship between electric and magnetic field amplitudes in an electromagnetic wave depends on the speed of light in that medium, not in vacuum. Since light travels slower in glass (by a factor of nn), the wave impedance changes—the magnetic field must be proportionally larger to carry the same energy. Use the fundamental wave relation E0=v⋅B0E_0 = v \cdot B_0, where v=c/nv = c/n is the speed in the medium.

Intuitive explanation

The key is recognizing that the relationship between electric and magnetic field amplitudes in an electromagnetic wave depends on the speed of light in that medium, not in vacuum. Since light travels slower in glass (by a factor of nn), the wave impedance changes—the magnetic field must be proportionally larger to carry the same energy. Use the fundamental wave relation E0=v⋅B0E_0 = v \cdot B_0, where v=c/nv = c/n is the speed in the medium.

Browse the problem library