Mathematics

Mathematics

Problem

- The value of ∫0∞[2e−x]dx\int_{0}^{\infty} [2e^{-x}] dx (where, [.][.] denotes the greatest integer function of xx ) is equal to a. 1 b. log⁡e2\log_e 2 c. 0 d. 1e\frac{1}{e}
Intuitive explanation

The greatest integer function [2e−x][2e^{-x}] takes different constant values on different intervals—your job is to find where those breakpoints occur. Since 2e−x2e^{-x} decreases from 22 to 00 as xx goes from 00 to ∞\infty, you'll split the integral into regions where [2e−x][2e^{-x}] equals 00, 11, or 22, then sum the contributions. This transforms a tricky floor-function integral into a sum of simple rectangular areas.

Intuitive explanation

The greatest integer function [2e−x][2e^{-x}] takes different constant values on different intervals—your job is to find where those breakpoints occur. Since 2e−x2e^{-x} decreases from 22 to 00 as xx goes from 00 to ∞\infty, you'll split the integral into regions where [2e−x][2e^{-x}] equals 00, 11, or 22, then sum the contributions. This transforms a tricky floor-function integral into a sum of simple rectangular areas.

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