Mathematics

Mathematics

Problem

If a\mathbf{a} , b\mathbf{b} , c\mathbf{c} and d\mathbf{d} are four coplanar points, then show that [abc]=[bcd]+[cad]+[abd][\mathbf{a} \mathbf{b} \mathbf{c}] = [\mathbf{b} \mathbf{c} \mathbf{d}] + [\mathbf{c} \mathbf{a} \mathbf{d}] + [\mathbf{a} \mathbf{b} \mathbf{d}]
Intuitive explanation

When four points lie in the same plane, their position vectors satisfy a linear dependence—one point can be expressed as a combination of the others. The key is to write d\mathbf{d} in terms of a\mathbf{a}, b\mathbf{b}, and c\mathbf{c}, then substitute into a scalar triple product. This transforms the left side into a sum of three products on the right, each representing how d\mathbf{d}'s "weight" distributes across the triangular regions formed by the other three points.

Intuitive explanation

When four points lie in the same plane, their position vectors satisfy a linear dependence—one point can be expressed as a combination of the others. The key is to write d\mathbf{d} in terms of a\mathbf{a}, b\mathbf{b}, and c\mathbf{c}, then substitute into a scalar triple product. This transforms the left side into a sum of three products on the right, each representing how d\mathbf{d}'s "weight" distributes across the triangular regions formed by the other three points.

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