Mathematics

Mathematics

Problem

Construct a continuous function on the closed interval [0,2][0,2] that attains its absolute maximum at x=1x=1 even though the derivative at x=1x=1 does not exist. Provide an explicit formula for such a function.
Intuitive explanation

The key insight is that a function can have a "sharp corner" or "cusp" at its maximum point, where the derivative fails to exist because the left and right slopes don't match. Think of an absolute value function or a similar V-shaped (or inverted V-shaped) curve: it's perfectly continuous, but the sharp peak prevents differentiability there. You need a function that's smooth everywhere except at x=1x=1, where it reaches its highest value with a sharp point.

Intuitive explanation

The key insight is that a function can have a "sharp corner" or "cusp" at its maximum point, where the derivative fails to exist because the left and right slopes don't match. Think of an absolute value function or a similar V-shaped (or inverted V-shaped) curve: it's perfectly continuous, but the sharp peak prevents differentiability there. You need a function that's smooth everywhere except at x=1x=1, where it reaches its highest value with a sharp point.

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