Physics
Physics
Problem
A stone X is dropped from rest from the roof of a building 80 m high. Exactly 1.5 s later, stone Y is projected vertically upward from ground level with a speed of 35 m/s. Using : a. (i) Calculate the time after Y is projected when the two stones are at the same height. b. (ii) Determine that height above the ground.Intuitive explanation
Both stones follow predictable parabolic paths under constant gravity—the key is setting up position equations for each and finding when they meet. Stone X starts high and falls; stone Y starts low and rises. Since Y is launched 1.5 s after X, you'll need to account for that time offset when writing their position functions. Once you have both expressions, set them equal to find the collision time and height.
Intuitive explanation
Both stones follow predictable parabolic paths under constant gravity—the key is setting up position equations for each and finding when they meet. Stone X starts high and falls; stone Y starts low and rises. Since Y is launched 1.5 s after X, you'll need to account for that time offset when writing their position functions. Once you have both expressions, set them equal to find the collision time and height.