Mathematics

Mathematics

Problem

The 3rd term of a geometric progression is 12 and the 6th term is 96. Find the common ratio.
Intuitive explanation

A geometric progression multiplies by the same factor each step, so the ratio between any two terms depends only on how many steps apart they are. Since you know two terms and their positions, you can set up an equation using the relationship an=a1⋅rn−1a_n = a_1 \cdot r^{n-1} — or more directly, notice that going from term 3 to term 6 is exactly 3 steps, so the 6th term equals the 3rd term times r3r^3. Use this to find rr without needing to find a1a_1 first.

Intuitive explanation

A geometric progression multiplies by the same factor each step, so the ratio between any two terms depends only on how many steps apart they are. Since you know two terms and their positions, you can set up an equation using the relationship an=a1⋅rn−1a_n = a_1 \cdot r^{n-1} — or more directly, notice that going from term 3 to term 6 is exactly 3 steps, so the 6th term equals the 3rd term times r3r^3. Use this to find rr without needing to find a1a_1 first.

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