Mathematics

Mathematics

Problem

Let fk(x)=x2+2kx+9f_k(x)=\sqrt{x^{2}+2kx+9}, where kk is a real parameter. Determine the set of all real values of kk for which the domain of fkf_k is R\mathbb{R}.
Intuitive explanation

For fk(x)f_k(x) to be defined for all real xx, the expression under the square root must never be negative. This means the quadratic x2+2kx+9x^2 + 2kx + 9 must be non-negative for every x∈Rx \in \mathbb{R}—in other words, it can't dip below the xx-axis. A quadratic stays non-negative everywhere exactly when its discriminant is non-positive, so you need to find which values of kk make the discriminant ≤0\leq 0.

Intuitive explanation

For fk(x)f_k(x) to be defined for all real xx, the expression under the square root must never be negative. This means the quadratic x2+2kx+9x^2 + 2kx + 9 must be non-negative for every x∈Rx \in \mathbb{R}—in other words, it can't dip below the xx-axis. A quadratic stays non-negative everywhere exactly when its discriminant is non-positive, so you need to find which values of kk make the discriminant ≤0\leq 0.

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