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Mathematics
Mathematics
Problem
If
y
=
sin
−
1
x
y = \sin^{-1} x
y
=
sin
−
1
x
, show that
(
1
−
x
2
)
d
2
y
d
x
2
−
x
d
y
d
x
=
0
(1 - x^2) \frac{d^2 y}{dx^2} - x \frac{dy}{dx} = 0
(
1
−
x
2
)
d
x
2
d
2
y
−
x
d
x
d
y
=
0
.
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