Grinstead-Snell-Probability · Problem 4.1.18

Conditional Probability

Mathematics · bayes-formula-diseases

Problem

A doctor assumes that a patient has one of three diseases d1d_1, d2d_2, or d3d_3. Before any test, he assumes an equal probability for each disease. He carries out a test that will be positive with probability .8.8 if the patient has d1d_1, .6.6 if he has disease d2d_2, and .4.4 if he has disease d3d_3. Given that the outcome of the test was positive, what probabilities should the doctor now assign to the three possible diseases?
Intuitive explanation

This is a classic application of Bayes' theorem, where you update your initial beliefs (prior probabilities) using new evidence (the test result). The key insight is that a positive test is more likely to occur if the patient has d1d_1 than the other diseases, so you should shift your probability mass toward d1d_1. You'll multiply each prior by its corresponding likelihood, then normalize so the three probabilities sum to 1.

Intuitive explanation

This is a classic application of Bayes' theorem, where you update your initial beliefs (prior probabilities) using new evidence (the test result). The key insight is that a positive test is more likely to occur if the patient has d1d_1 than the other diseases, so you should shift your probability mass toward d1d_1. You'll multiply each prior by its corresponding likelihood, then normalize so the three probabilities sum to 1.

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