Physics

Physics

Problem

The force of interaction between two atoms is given by F=αβexp⁡(−x2αkT)F = \alpha\beta \exp\left(-\frac{x^2}{\alpha kT}\right); where xx is the distance, kk is the Boltzmann constant and TT is temperature and α\alpha and β\beta are two constants. The dimensions of β\beta is: a. M0L2T−4M^0L^2T^{-4} b. M2LT−4M^2LT^{-4} c. MLT−2MLT^{-2} d. M2L2T−2M^2L^2T^{-2}
Intuitive explanation

This problem tests whether you can extract dimensions from a physically meaningful equation. The key insight is that the exponential argument must be dimensionless—so x2αkT\frac{x^2}{\alpha kT} has no units—which immediately tells you what α\alpha must be. Once you know α\alpha's dimensions, you can work backward from the fact that FF (a force) equals αβ\alpha\beta times a dimensionless exponential to find β\beta's dimensions.

Intuitive explanation

This problem tests whether you can extract dimensions from a physically meaningful equation. The key insight is that the exponential argument must be dimensionless—so x2αkT\frac{x^2}{\alpha kT} has no units—which immediately tells you what α\alpha must be. Once you know α\alpha's dimensions, you can work backward from the fact that FF (a force) equals αβ\alpha\beta times a dimensionless exponential to find β\beta's dimensions.

Browse the problem library