Mathematics

Mathematics

Problem

Provide an explicit differentiable function ff such that f′(0)=0f'(0)=0 but x=0x=0 is not a local extremum of ff. State the function and give a brief reason supporting your claim.
Intuitive explanation

The key is finding a function whose derivative touches zero at a point but doesn't change sign there—so the function keeps increasing (or decreasing) right through it. Think of f(x)=x3f(x) = x^3: the tangent line is perfectly horizontal at x=0x=0, yet the function is strictly increasing everywhere. The derivative f′(x)=3x2f'(x) = 3x^2 equals zero at x=0x=0, but for x<0x < 0 the function is below zero and for x>0x > 0 it's above, so there's no local max or min, just an inflection point where the curve changes concavity.

Intuitive explanation

The key is finding a function whose derivative touches zero at a point but doesn't change sign there—so the function keeps increasing (or decreasing) right through it. Think of f(x)=x3f(x) = x^3: the tangent line is perfectly horizontal at x=0x=0, yet the function is strictly increasing everywhere. The derivative f′(x)=3x2f'(x) = 3x^2 equals zero at x=0x=0, but for x<0x < 0 the function is below zero and for x>0x > 0 it's above, so there's no local max or min, just an inflection point where the curve changes concavity.

Browse the problem library