Mathematics

Mathematics

Problem

Let g(x)=∫0xf(t) dtg(x)=\displaystyle\int_{0}^{x} f(t)\,dt. The function ff satisfies f(x)<0f(x)<0 on (−3,−1)(-3,-1) and (2,5)(2,5) and f(x)>0f(x)>0 for all other xx. Determine the open interval(s) on which gg is decreasing.
Intuitive explanation

The key insight is that gg is the antiderivative of ff, so g′(x)=f(x)g'(x) = f(x) by the Fundamental Theorem of Calculus. A function decreases exactly where its derivative is negative. Since you know where ff is negative, you've already identified where gg must be decreasing—no integration needed, just apply the relationship between a function and its derivative.

Intuitive explanation

The key insight is that gg is the antiderivative of ff, so g′(x)=f(x)g'(x) = f(x) by the Fundamental Theorem of Calculus. A function decreases exactly where its derivative is negative. Since you know where ff is negative, you've already identified where gg must be decreasing—no integration needed, just apply the relationship between a function and its derivative.

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