Physics

Physics

Problem

For 1≤t≤31\le t\le3 seconds, a particle’s position along a straight line is s(t)=t4−4t2+2s(t)=t^{4}-4t^{2}+2 meters. Determine the particle’s average acceleration on this interval.
Intuitive explanation

Average acceleration is just the total change in velocity divided by the time elapsed—think of it as how much the particle's speed direction or magnitude shifted overall. You don't need to find acceleration at every instant; instead, find the velocity at the endpoints (t=1t=1 and t=3t=3) using the derivative v(t)=s′(t)v(t)=s'(t), then apply the definition aavg=ΔvΔta_{\text{avg}}=\frac{\Delta v}{\Delta t}.

Intuitive explanation

Average acceleration is just the total change in velocity divided by the time elapsed—think of it as how much the particle's speed direction or magnitude shifted overall. You don't need to find acceleration at every instant; instead, find the velocity at the endpoints (t=1t=1 and t=3t=3) using the derivative v(t)=s′(t)v(t)=s'(t), then apply the definition aavg=ΔvΔta_{\text{avg}}=\frac{\Delta v}{\Delta t}.

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