Problem

Problem

Find all possible triplets (x,y,z)(x, y, z) such that (x+y)+(y+2z)cos⁡2θ+(z−x)sin⁡2θ=0(x+y) + (y+2z) \cos 2\theta + (z-x) \sin^2 \theta = 0 , for all θ\theta .
Intuitive explanation

The key insight is that if an expression involving θ\theta equals zero for all values of θ\theta, then each independent component must vanish separately. Rewrite the equation by expressing everything in terms of cos⁡2θ\cos 2\theta and sin⁡2θ\sin^2 \theta (or equivalently, collect coefficients of linearly independent trigonometric functions). Since the equation must hold for every θ\theta, the coefficient of each independent term—and the constant term—must all equal zero. This gives you a system of linear equations in xx, yy, and zz to solve.

Intuitive explanation

The key insight is that if an expression involving θ\theta equals zero for all values of θ\theta, then each independent component must vanish separately. Rewrite the equation by expressing everything in terms of cos⁡2θ\cos 2\theta and sin⁡2θ\sin^2 \theta (or equivalently, collect coefficients of linearly independent trigonometric functions). Since the equation must hold for every θ\theta, the coefficient of each independent term—and the constant term—must all equal zero. This gives you a system of linear equations in xx, yy, and zz to solve.

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