Mathematics

Mathematics

Problem

Statement I The function f(x)=xsin⁡xf(x) = x \sin x and f′(x)=xcos⁡x+sin⁡xf'(x) = x \cos x + \sin x are both non-periodic. Statement II The derivative of differentiable function (non-periodic) is non-periodic function.
Intuitive explanation

The key insight is that periodicity is about repeating behavior over a fixed interval—but products and sums of periodic and non-periodic functions often destroy that pattern. For Statement I, even though sin⁡x\sin x is periodic, multiplying by the non-periodic factor xx stretches the oscillations unpredictably, and the derivative xcos⁡x+sin⁡xx\cos x + \sin x inherits this non-repeating nature. Statement II asks whether this is always true: does differentiating a non-periodic function guarantee a non-periodic result? The answer hinges on finding a counterexample—a non-periodic function whose derivative is periodic.

Intuitive explanation

The key insight is that periodicity is about repeating behavior over a fixed interval—but products and sums of periodic and non-periodic functions often destroy that pattern. For Statement I, even though sin⁡x\sin x is periodic, multiplying by the non-periodic factor xx stretches the oscillations unpredictably, and the derivative xcos⁡x+sin⁡xx\cos x + \sin x inherits this non-repeating nature. Statement II asks whether this is always true: does differentiating a non-periodic function guarantee a non-periodic result? The answer hinges on finding a counterexample—a non-periodic function whose derivative is periodic.

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