Mathematics

Mathematics

Problem

Consider the function q(x)={x2−9x−3,x<3,(x−3)3,x≥3.q(x)= \begin{cases} \dfrac{x^2-9}{x-3}, & x<3,\\ (x-3)^3, & x\ge 3. \end{cases} Does qq have a vertical asymptote at x=3x=3? Justify your answer using limits.
Intuitive explanation

The key is to check whether the function blows up to infinity as you approach x=3x=3, or whether it actually settles to a finite value. For x<3x<3, simplify the rational expression by factoring—you'll find the apparent discontinuity cancels out, giving you a real limit. Then compare that limit to what happens from the right at x=3x=3. A vertical asymptote only exists if the function diverges to ±∞\pm\infty; if both one-sided limits are finite, there's no asymptote, just a removable discontinuity or jump.

Intuitive explanation

The key is to check whether the function blows up to infinity as you approach x=3x=3, or whether it actually settles to a finite value. For x<3x<3, simplify the rational expression by factoring—you'll find the apparent discontinuity cancels out, giving you a real limit. Then compare that limit to what happens from the right at x=3x=3. A vertical asymptote only exists if the function diverges to ±∞\pm\infty; if both one-sided limits are finite, there's no asymptote, just a removable discontinuity or jump.

Browse the problem library