Blundell Thermal Physics · Problem 12.1

Isothermal and adiabatic processes

Physics — Statistical Mechanics · adiabatic-expansion-ideal-gas

Problem

In an adiabatic expansion of an ideal gas, pVγpV^\gamma is constant. Show also that TVγ−1=constant,T=constant×p1−1/γ.(12.23)\begin{aligned} TV^{\gamma-1} &= \text{constant}, \tag{12.23}\\ T &= \text{constant} \times p^{1-1/\gamma}. \end{aligned}
Intuitive explanation

In adiabatic processes, the constraint pVγ=constantpV^\gamma = \text{constant} captures the interplay between pressure, volume, and temperature without heat exchange. To find the other two relations, use the ideal gas law pV=nRTpV = nRT to eliminate one variable at a time—swapping pp for TT in the first relation gives you equation (12.23), and then combining both constraints yields (12.24). The key insight is that all three equations describe the same adiabatic path, just expressed in different variable pairs.

Intuitive explanation

In adiabatic processes, the constraint pVγ=constantpV^\gamma = \text{constant} captures the interplay between pressure, volume, and temperature without heat exchange. To find the other two relations, use the ideal gas law pV=nRTpV = nRT to eliminate one variable at a time—swapping pp for TT in the first relation gives you equation (12.23), and then combining both constraints yields (12.24). The key insight is that all three equations describe the same adiabatic path, just expressed in different variable pairs.

Related theory

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