FYKOS Year 30 Series 2 Problem 2 — ultra high temperature superconducticvity · FYKOS 30 #30.2.2

Physics · electromagnetism · thermodynamics

Problem

Many types of materials, mostly metals, have increasing dependence of resistivity on temperature. However, there are semiconductors or graphite which show a decreasing dependence. And you have also probably heard about superconductivity, the natural phenomenon when a cooled material shows almost no electrical resistance and becomes a perfect conductor. Our current state of knowledge says that the temperature of a superconductor must be well below room temperature, but let's assume that the equation defining the resistance is R=R= R_{0} (1 + αΔt)$,where, where R_{0}istheresistanceatroomtemperature, the resistance at room temperature, αisthetemperaturecoefficientofresistanceand the temperature coefficient of resistance and Δtisthetemperaturedifferencewithrespecttoroomtemperature,andtheequationholdsforanytemperature.Usingthisequationandcoefficients is the temperature difference with respect to room temperature, and the equation holds for any temperature. Using this equation and coefficients α_{C}=-0.5\cdot 10^{-3}K^{−1}forgraphiteand for graphite and α_{Si}=-75\cdot 10^{-3}K^{−1}$ for silicon, we obtain zero resistance for high temperatures. Determine these two temperatures and explain why the superconducting phenomenon does not work this way, i.e. neither carbon nor silicon are superconductors at high temperatures.
Intuitive explanation

The core concept here is using a linear resistance-temperature model to find where RR mathematically reaches zero, then recognizing why this prediction fails physically. For each material, you'll set R=0R = 0 in the given equation and solve for Δt\Delta t—but the real insight is that this linear approximation breaks down at extreme temperatures; materials don't actually maintain constant α\alpha as temperature climbs, and long before reaching that calculated point, other physical effects (like thermal ionization, material breakdown, or phase changes) dominate and invalidate the simple model. Understanding the limits of a formula is as important as using it correctly.

Intuitive explanation

The core concept here is using a linear resistance-temperature model to find where RR mathematically reaches zero, then recognizing why this prediction fails physically. For each material, you'll set R=0R = 0 in the given equation and solve for Δt\Delta t—but the real insight is that this linear approximation breaks down at extreme temperatures; materials don't actually maintain constant α\alpha as temperature climbs, and long before reaching that calculated point, other physical effects (like thermal ionization, material breakdown, or phase changes) dominate and invalidate the simple model. Understanding the limits of a formula is as important as using it correctly.

Related theory

Browse the problem library