Physics

This problem connects power, work, and energy by asking you to find time when power is held constant. The key insight is that power is the rate at which work is done: $P = \frac{W}{t}$. Since the elevator does work against gravity to lift the mass through a height, you can find the total work needed ($W = mgh$), then use the constant power to solve for time. It's a direct application of the power definition—no need to worry about acceleration or forces separately.

This problem connects power, work, and energy by asking you to find time when power is held constant. The key insight is that power is the rate at which work is done: $P = \frac{W}{t}$. Since the elevator does work against gravity to lift the mass through a height, you can find the total work needed ($W = mgh$), then use the constant power to solve for time. It's a direct application of the power definition—no need to worry about acceleration or forces separately.