Physics
Physics
Problem
A candle high is placed in front of a concave mirror. The image is formed in front of the mirror. Calculate the height of the image and state whether it is erect or inverted.Intuitive explanation
This problem combines the mirror equation with magnification — two sides of the same optical coin. Once you know where the object and image sit relative to the mirror, magnification tells you how much the image is stretched or shrunk and whether it flips. The key is that magnification relates the ratio of image distance to object distance, which directly gives you the image height and reveals the image's orientation through its sign.
Intuitive explanation
This problem combines the mirror equation with magnification — two sides of the same optical coin. Once you know where the object and image sit relative to the mirror, magnification tells you how much the image is stretched or shrunk and whether it flips. The key is that magnification relates the ratio of image distance to object distance, which directly gives you the image height and reveals the image's orientation through its sign.