Problem

Problem

If a<b<c<da < b < c < d , then show that (x−a)(x−c)+3(x−b)(x−d)=0 has real and distinct roots.(x - a)(x - c) + 3(x - b)(x - d) = 0 \text{ has real and distinct roots.}
Intuitive explanation

The key is to rewrite this as a quadratic and show its discriminant is always positive. Expand both products and combine like terms to get a standard quadratic form, then compute the discriminant Δ=B2−4AC\Delta = B^2 - 4AC. The trick is recognizing that the ordering a<b<c<da < b < c < d creates a specific algebraic structure—when you substitute the midpoints or use the constraint that bb and dd are positioned between aa and cc, the discriminant simplifies to an expression that's manifestly positive, guaranteeing two real distinct roots.

Intuitive explanation

The key is to rewrite this as a quadratic and show its discriminant is always positive. Expand both products and combine like terms to get a standard quadratic form, then compute the discriminant Δ=B2−4AC\Delta = B^2 - 4AC. The trick is recognizing that the ordering a<b<c<da < b < c < d creates a specific algebraic structure—when you substitute the midpoints or use the constraint that bb and dd are positioned between aa and cc, the discriminant simplifies to an expression that's manifestly positive, guaranteeing two real distinct roots.

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