Chemistry

Chemistry

Problem

When zinc reacts with very dilute HNO3\text{HNO}_3, the oxidation state of nitrogen changes from: a. +5 to +1 b. +5 to -3 c. +5 to +4 d. +5 to +3
Intuitive explanation

Nitrogen's oxidation state in dilute nitric acid depends on what product forms—and that's determined by how much oxidizing power is available. With very dilute HNO3\text{HNO}_3, there's limited nitric acid to act as an oxidizer, so zinc reduces nitrogen to a lower oxidation state than in concentrated acid. The key is recognizing that dilute conditions favor reduction to NH4+\text{NH}_4^+ (where N is −3-3) rather than NO2\text{NO}_2 or NO\text{NO}, making this a more dramatic reduction than you might initially expect.

Intuitive explanation

Nitrogen's oxidation state in dilute nitric acid depends on what product forms—and that's determined by how much oxidizing power is available. With very dilute HNO3\text{HNO}_3, there's limited nitric acid to act as an oxidizer, so zinc reduces nitrogen to a lower oxidation state than in concentrated acid. The key is recognizing that dilute conditions favor reduction to NH4+\text{NH}_4^+ (where N is −3-3) rather than NO2\text{NO}_2 or NO\text{NO}, making this a more dramatic reduction than you might initially expect.

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