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Mathematics
Problem
The distribution of a variable
X
X
X
is given by the law
f
(
x
)
=
1
5
2
π
e
−
1
2
(
x
−
100
5
)
2
f(x) = \frac{1}{5\sqrt{2\pi}} e^{-\frac{1}{2}\left(\frac{x-100}{5}\right)^2}
f
(
x
)
=
5
2
π
1
e
−
2
1
(
5
x
−
100
)
2
. Write down the values of mean and S.D. (March 2009) (QB) Also find variance.
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